Answer:
the pressure exerted on the turf when the player lands on his knee is 240,000 N/m².
Explanation:
Given;
combined weight of the players, F = 2400 N
measurement of the player's knee = 0.1 m by 0.1 m
The area of the player's knee is calculated as;
A = 0.1 m x 0.1 m = 0.01 m²
The pressure exerted on the turf when the player lands on his knee is calculated as;
P = F / A
P = (2400 N) / (0.01 m²)
P = 240,000 N/m²
Therefore, the pressure exerted on the turf when the player lands on his knee is 240,000 N/m².
