help me answer this question please

9514 1404 393
Answer:
7953.873
Step-by-step explanation:
The first derivative is ...
f'(x) = 4·3x²·e^x +4x³·e^x = e^x(4x³ +12x²)
Then the second derivative is ...
f''(x) = (12x² +24x)e^x +(4x³ +12x²)e^x
f''(x) = e^x(4x³ +24x² +24x)
So, f''(3) = (e^3)(4·27 +24·9 +24·3) = 396e^3 = 7953.87262158
Rounded to thousandths, this is ...
f''(3) = 7953.873
Answer:
f''(x) ≈ 7953.87
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Algebra I
Calculus
Derivatives
Basic Power Rule:
Product Rule: [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]
Derivative Rule: [tex]\displaystyle \frac{d}{dx} [e^x]=e^x[/tex]
Step-by-step explanation:
Step 1: Define
f(x) = 4x³eˣ
f''(x) is x = 3 for 2nd Derivative
Step 2: Differentiate
Step 3: Evaluate