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what is the mass in grams of a sample of 7.3 x 10^23 molecules of (iodine heptafluoride) IF7

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Answer:

320 g IF₇

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

7.3 × 10²³ molecules IF₇

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of I - 126.90 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of IF₇ - 126.90 + 7(19.00) = 259.9 g/mol

Step 3: Convert

  1. Set up:                               [tex]\displaystyle 7.3 \cdot 10^{23} \ molecules \ IF_7(\frac{1 \ mol \ IF_7}{6.022 \cdot 10^{23} \ molecules \ IF_7})(\frac{259.9 \ g \ IF_7}{1 \ mol \ IF_7})[/tex]
  2. Multiply/Divide:                                                                                                 [tex]\displaystyle 315.056 \ g \ IF_7[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

315.056 g IF₇ ≈ 320 g IF₇

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