What is the area of the regular hexagon ABCEF? Explain your reasoning.

Answer:
1350[tex]\sqrt{3}[/tex] units²
Step-by-step explanation:
The regular hexagon consists of 6 equiangular triangles
The area (A) of a equilateral triangle is calculated as
A = [tex]\frac{s^2\sqrt{3} }{4}[/tex] ( s is the side length )
Here s = 30 , then
A = [tex]\frac{30^2\sqrt{3} }{4}[/tex] = [tex]\frac{900\sqrt{3} }{4}[/tex] = 225[tex]\sqrt{3}[/tex] units²
Thus the area of the regular hexagon is
area = 6 × 225[tex]\sqrt{3}[/tex]
= 1350[tex]\sqrt{3}[/tex] units² ← exact value
≈ 2338.3 units² ( to 1 dec. place )