Answer:
The force of kinetic friction between the block and the floor is 2.4 N
Explanation:
The given parameters are;
The weight of the block = 8 Newtons
The velocity of the block = Constant velocity
Taking the kinetic friction for wood, [tex]\mu _k[/tex] = 0.3, we have;
The normal reaction of the block on horizontal ground, N = The weight of the block = 8 N
The force of kinetic friction between , [tex]F_k[/tex] = [tex]\mu _k[/tex] × N
Therefore, we have;
The force of kinetic friction between the block and the floor, [tex]F_k[/tex] = 0.3 × 8 N = 2.4 N.
