If CB =3(x+8) and AD= 4(x+3), find AB

CD=CA+AB+BD
AB=CD-CA-BD
AB=CD-BD-BD
AB=CD-2.BD
AB=CD-2(BC+CD)
AB=CD-2BC-2CD
AB=-(CD+2BC)
AB=-{98-6(x+8)}
AB= 6x-50