Answer:
The equation of the line that passes through the points (7,-8) and (2, -8) is [tex]\mathbf{y=-8}[/tex]
Step-by-step explanation:
We need to write the equation of the line that passes through the points (7,-8) and (2, -8).
We need to write answer in fully reduced point-slope form, unless it is a vertical or horizontal line.
The general equation of point-slope form is: [tex]y-y_1=m(x-x_1)[/tex]
where m is slope of the line.
To find the slope, we can use formula: [tex]Slope=\frac{y_2-y_1}{x_2-x_1}[/tex]
We have [tex]x_1=7,y_1=-8,x_2=2, y_2=-8[/tex]
Putting values and finding slope:
[tex]Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-8-(-8)}{2-7}\\Slope=\frac{-8+8}{-5}\\Slope=\frac{0}{-5}\\Slope=0[/tex]
So, we find the slope : m = 0
Now, using the point (7,-8) and slope m =0, the required equation is:
[tex]y-y_1=m(x-x_1)\\y-(-8)=0(x-7)\\y+8=0\\y=-8[/tex]
So, the equation of the line that passes through the points (7,-8) and (2, -8) is [tex]\mathbf{y=-8}[/tex]
