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The diagram represents the path of a ball that has been thrown upward. Discuss how the kinetic energy (KE), gravitational potential energy (GPE), and total mechanical energy (ME) change between points A (where the ball is thrown from), B (the highest point reached by the ball), and C (where the ball hits the ground). Ignore friction between the ball and the air. (3 points)

The diagram represents the path of a ball that has been thrown upward Discuss how the kinetic energy KE gravitational potential energy GPE and total mechanical class=

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xero099

Answer:

Gravitational potential energy: [tex]GPE_{B}>GPE_{A}>GPE_{C}[/tex]

Kinetic energy: [tex]KE_{B}<KE_{A}<KE_{C}[/tex]

Total mechanical energy: [tex]ME_{A}=ME_{B}=ME_{C}[/tex]

Explanation:

The gravitational potential energy is directly proportional to height ([tex]GPE_{B}>GPE_{A}>GPE_{C}[/tex]). Since there are no non-conservative forces, the total mechanical energy is conserved ([tex]ME_{A}=ME_{B}=ME_{C}[/tex]) and the total mechanical energy is the sum of gravitational potential and kinetic energies. Then:

[tex]GPE_{A} + KE_{A} = GPE_{B} + KE_{B} = GPE_{C} + KE_{C}[/tex] (1)

If we know that [tex]GPE_{B}>GPE_{A}>GPE_{C}[/tex], then we conclude the following inequation for the kinetic energy:

[tex]KE_{B}<KE_{A}<KE_{C}[/tex] (2)