Answer:
b) The slope of line is 20
c) The equation in slope-intercept form is: [tex]\mathbf{y=20x}[/tex]
d) i) she would have travelled 1480 m after 74 s
ii) It will take 125 s to travel 2.5 km
Step-by-step explanation:
Part b: Slope of Line
Slope of line can be found using formula: [tex]Slope=\frac{y_2-y_1}{x_2-x_1}[/tex]
From the table we can take any two points and find the slope.
Looking at the graph, the time is x-axis and distance is y-axis
Let we take (0,0) and (8,160)
So, we have: [tex]x_1=0, y_1=0, x_2=8, y_2=160[/tex]
Now finding Slope:
[tex]Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{160-0}{8-0} \\Slope=\frac{160}{8}\\Slope=20[/tex]
So, the slope of line is 20
Part c) Find the equation in slope-intercept form
The general equation of slope-intercept form is: [tex]y=mx+b[/tex] where m is slope and b is y-intercept
We have found slope, m = 20
We need to find y-intercept.
y-intercept can be found by putting x-axis (time) equal to zero and check what the y-axis (distance) is:
So, when x =0, y=0
So, y-intercept = 0
The equation will be:
[tex]y=mx+b\\y=20x+0\\y=20x[/tex]
The equation in slope-intercept form is: [tex]\mathbf{y=20x}[/tex]
Part d)
Part i) How far will she have travelled after 74 s
We are given time (x) = 74 s
We need to find distance i.e. y:
Using the equation: [tex]\mathbf{y=20x}[/tex]
Put x = 74
[tex]y=20x\\y=20(74)\\y=1480[/tex]
So, she would have travelled 1480 m after 74 s
Part ii) How long will it take to travel 2.5 km
We are given distance (y) = 2.5 km
We need to find time i.e. x:
Using the equation: [tex]\mathbf{y=20x}[/tex]
Since distance is given in meters but here it is in km
So converting 2.5 km into m
We know that 1 km = 1000m
So, 2.5 km = 2500 m
Now finding time:
[tex]y=20x\\2500=20(x)\\x=\frac{2500}{20}\\x=125[/tex]
So, It will take 125 s to travel 2.5 km
