Answer:
The value of x in terms of b is: [tex]\mathbf{x=-\frac{6}{2b}}[/tex]
The value of x when b is 3 is: x = -1
Step-by-step explanation:
We are given the function: [tex]-2(bx-5)=16[/tex]
First we need to find
The value of x in terms of b
We need to find value of x
[tex]-2(bx-5)=16[/tex]
Multiply -2 with terms inside the bracket
[tex]-2bx+10=16[/tex]
Subtract 10 from both sides
[tex]-2bx+10-10=16-10\\-2bx=6[/tex]
Divide both sides by -2b
[tex]\frac{-2bx}{-2b}=\frac{6}{-2b}\\x=-\frac{6}{2b}[/tex]
So, The value of x in terms of b is: [tex]\mathbf{x=-\frac{6}{2b}}[/tex]
The value of x when b is 3
We have the equation for the value of x in terms of b:
[tex]\mathbf{x=-\frac{6}{2b}}[/tex]
Put b = 3
[tex]x=-\frac{6}{2(3)}\\x=-\frac{6}{6}\\x=-1[/tex]
So, The value of x when b is 3 is: x = -1
