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Answer:
Stan ran 4 and StartFraction 7 Over 10 EndFraction miles, which was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran. Four students wrote and solved equations to find m, the number of miles that Matt ran. Which student wrote and solved the equation correctly?Stan ran 4 and StartFraction 7 Over 10 EndFraction miles, which was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran. Four students wrote and solved equations to find m, the number of miles that Matt ran. Which student wrote and solved the equation correctly?Stan ran 4 and StartFraction 7 Over 10 EndFraction miles, which was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran. Four students wrote and solved equations to find m, the number of miles that Matt ran. Which student wrote and solved the equation correctly?Stan ran 4 and StartFraction 7 Over 10 EndFraction miles, which was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran. Four students wrote and solved equations to find m, the number of miles that Matt ran. Which student wrote and solved the equation correctly?Stan ran 4 and StartFraction 7 Over 10 EndFraction miles, which was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran. Four students wrote and solved equations to find m, the number of miles that Matt ran. Which student wrote and solved the equation correctly?
Step-by-step explanation:
Stan ran 4 and StartFraction 7 Over 10 EndFraction miles, which was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran. Four students wrote and solved equations to find m, the number of miles that Matt ran. Which student wrote and solved the equation correctly?Stan ran 4 and StartFraction 7 Over 10 EndFraction miles, which was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran. Four students wrote and solved equations to find m, the number of miles that Matt ran. Which student wrote and solved the equation correctly?
Answer:
[tex]b+1\\b+2\\b+(b+1)+(b+2)=24[/tex]
Step-by-step explanation:
If [tex]b[/tex] represents the youngest brother's age, the second oldest brother's age can be written as [tex]b+1[/tex] and the third can be written as [tex]b+2[/tex], since they're all consecutive.
The sum of all their ages is then [tex]b+(b+1)+(b+2)[/tex] which is equal to [tex]24[/tex], as given.