Use your knowledge of special right triangles to find y. Write your answer in simplest radical form.
Please be quick

Answer:
[tex] \sin(30°) = \frac{10}{y} \\ \frac{1}{2} = \frac{10}{y} \\ \boxed{y = 20 \: mi}[/tex]
or,
[tex] \cos(60°) = \frac{10}{y} \\ \frac{1}{2} = \frac{10}{y} \\ \boxed{y = 20 \: mi}[/tex]