Answer:
9.6724 g MgO
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Stoichiometry
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
Step 1: Define
[RxN - Balanced] 2Mg + O₂ → 2MgO
[Given] 5.8332 g Mg
Step 2: Identify Conversions
[RxN] 2 mol Mg = 2 mol MgO
Molar Mass of Mg - 24.31 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of MgO - 24.31 + 16.00 = 40.31 g/mol
Step 3: Stoichiometry
- Set up: [tex]\displaystyle 5.8332 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{2 \ mol \ MgO}{2 \ mol \ Mg})(\frac{40.31 \ g \ MgO}{1 \ mol \ MgO})[/tex]
- Multiply/Divide: [tex]\displaystyle 9.67241 \ g \ MgO[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 5 sig figs.
9.67241 g MgO ≈ 9.6724 g MgO
