Answer:
[tex]\boxed{=3}[/tex]
Solution Steps:
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1.) Divide [tex]\bold{\frac{2x2+3}{3}}[/tex] by [tex]\bold{\frac{8}{9}}[/tex] by multiplying [tex]\bold{\frac{2x2+3}{3}}[/tex] by the reciprocal of [tex]\bold{\frac{8}{9}}[/tex]:
- [tex]{\frac{(2x2+3)x9}{3x8}}[/tex]
Equation at the end of Step 3:
- [tex]{\frac{(2x2+3)x9}{3x8}}[/tex]
2.) Cancel out 3 in both numerator and denominator:
- [tex]{\frac{(2x2+3)x9}{3x8}=\frac{3(2+6)}{8}}[/tex]
- We cancel out the 3's by getting rid of the 3 on the denominator.
Equation at the end of Step 3:
- [tex]\frac{3(2+6)}{8}}[/tex]
3.) Multiply 2 and 3:
- [tex]2[/tex] × [tex]3=8[/tex]
Equation at the end of Step 3:
4.) Multiply 3 and 8:
- [tex]3[/tex] × [tex]8=24[/tex]
Equation at the end of Step 4:
5.) Divide 24 by 8:
- [tex]24[/tex] ÷ [tex]8=3[/tex]
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