Answer:
1.28 mol Cu(OH)₂
General Formulas and Concepts:
Chemistry - Atomic Structure
Explanation:
Step 1: Define
125 g Cu(OH)₂
Step 2: Identify Conversions
Molar Mass of Cu - 63.55 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of Cu(OH)₂ - 63.55 + 2(16.00) + 2(1.01) = 97.57 g/mol
Step 3: Convert
[tex]125 \ g \ Cu(OH)_2(\frac{1 \ mol \ Cu(OH)_2}{97.57 \ g \ Cu(OH)_2} )[/tex] = 1.28113 mol Cu(OH)₂
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
1.28113 mol Cu(OH)₂ ≈ 1.28 mol Cu(OH)₂
