The required standard deviation is 0.65
Given data is,
Computation:
[tex]\varepsilon_x\times P(X=x)=0\times 0.09+1\times0.42+2\times0.49\\=0.42+0.98\\=1.4[/tex]
Now,
[tex]E(X^2)=0^2\times 0.009+1^2\times 0.42+2^2\times 0.49\\=0.42+1.96\\=2.38\\\sigma ^2=E(X^2)-(E(X))^2\\=2.38-(1.4)^2\\=0.42\\\sigma =\sqrt{0.42}\\=0.65[/tex]
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