Answer:
104.7 in^3
Step-by-step explanation:
Step one:
given data
The ball has a radius of 5 inches and
the cylinder has a height of 8 inches
Step two:
The volume of the cylinder
[tex]v= \pi r^2 h[/tex]
substitute our data
[tex]v= 3.142*5^2*8\\\\v=628.4in^3[/tex]
The volume of the ball
[tex]v=4/3 \pi r^3[/tex]
substitute our data
[tex]v= 4/3 *3.142*5^3\\\\v= 523.7 in^3[/tex]
The space will have a volume of
=628.4-523.7
=104.7 in^3
