Answer:
The resistance of the coil is 4 Ω.
Explanation:
The resistance (R) of the coil can be calculated using the following equation:
[tex]R = \frac{\rho L}{A}[/tex]
Where:
ρ: is the resistivity of copper = 0.02x10⁻⁶ Ωm
L: is the length of the coil
A: is the cross-sectional area = 0.8 mm² = 8x10⁻⁷ m²
The length of the coil is given by:
[tex] L = 200 turn* 80 cm/turn = 16000 cm = 160 m [/tex]
Now, the resistance is:
[tex]R = \frac{\rho L}{A} = \frac{0.02 \cdot 10^{-6} \Omega m*160 m}{8 \cdot 10^{-7} m^{2}} = 4 \Omega[/tex]
Therefore, the resistance of the coil is 4 Ω.
I hope it helps you!
