A population of insects increases at the rate of 200 10t 13t2 what is the change in the population of insects between day 0 and day 3

Respuesta :

Answer:

762 days

Step-by-step explanation:

Given

[tex]Rate = 200 + 10t + 13t^2[/tex]

Let the rate be R.

So the rate change with time is represented as:

[tex]\frac{dR}{dt} = 200 +10t + 13t^2[/tex]

So:

[tex]dR = (200 + 10t + 13t^2)\ dt[/tex]

To get the number of insects between day 0 and day 3, we need to integrate dR and set the bounds to 0 and 3

i.e.

[tex]dR = (200 + 10t + 13t^2)\ dt[/tex] becomes

[tex]\int\limits^3_0 {dR} \, =\int\limits^3_0 (200 + 10t + 13t^2)\ dt[/tex]

[tex]R =\int\limits^3_0 (200 + 10t + 13t^2)\ dt[/tex]

Integrate

[tex]R = 200t + \frac{10t^2}{2} + \frac{13t^3}{3} [3,0][/tex]

Solve for R by substituting 0 and 3 for t

[tex]R = (200*3 + \frac{10*3^2}{2} + \frac{13*3^3}{3}) - ( 200*0 + \frac{10*0^2}{2} + \frac{13*0^3}{3})[/tex]

[tex]R = (200*3 + \frac{10*9}{2} + \frac{13*27}{3}) - (0 + \frac{10}{2} + \frac{0}{3})[/tex]

[tex]R = (200*3 + 5*9 + 13*9) - (0)[/tex]

[tex]R = 600 + 45 + 117 - 0[/tex]

[tex]R =762[/tex]

The population of insect between the required interval is 762

The required change in the population of insects between day 0 and day 3 is 762.

Given that,

A population of insects increases at the rate of 200++ 10t + 13t2.

We have to determine,

What is the change in the population of insects between day 0 and day 3.

According to the question,

The rate change with time is represented as:

[tex]\frac{dr}{dt} = 200+10t+13t^{2}[/tex]

To determine the change in the population of insects between day 0 and day 3,

Integrating the given function with respect to time with limit 0 days to 3 days.

[tex]\int\limits^3_0 dr = \int\limits^3_0 (200+10t+13t^{2} ). dt\\\\\int\limits^3_0dr =\int\limits^3_0 \, 200dt + \int\limits^3_0 10tdt +\int\limits^3_0{13t^{2} dt\\\\\\\\R = [200t]^3_0 + [5t^{2} ]^3_0 + [\frac{13t^{3} }{3} ]^3_0\\\\R = 200[(3) - (0)] + 5 (3^{2} - 0^{2} ) + \frac{13}{3} [ 3^{3} - 0^{3} ]\\\\R = 200(3) + 5 (9) + \frac{13}{3}(27)\\\\R = 600+45+117\\\\R = 762[/tex]

Hence, The required change in the population of insects between day 0 and day 3 is 762.

To know more about Rate change click the link given below.

https://brainly.com/question/24540629