Answer:
The value is [tex]CP = 0.667[/tex]
Step-by-step explanation:
From the question we are told that
The resistance is [tex]R = 45 \pm 0.32\ \Omega[/tex]
The mean is [tex]\mu = 50 \Omega[/tex]
The standard deviation is [tex]\sigma = 0.16 \Omega[/tex]
Generally the upper limit of the resistance specified in the question(i.e upper specification limit (USL )) is
[tex]USL = 45 + 0.32 = 45.32 \ \Omega[/tex]
Generally the lower limit of the resistance specified in the question(i.e lower specification limit (USL )) is
[tex]LSL = 45 - 0.32 = 44.68 \ \Omega[/tex]
Generally the CP of the process of manufacturing the resistor is mathematically represented as
[tex]C P = \frac{ USL - LSL }{ 6 * \sigma }[/tex]
=> [tex]CP = \frac{45.32 - 44.68 }{6 * 0.16}[/tex]
=> [tex]CP = \frac{0.64 }{0.96}[/tex]
=> [tex]CP = 0.667[/tex]