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Madeline fires a bullet horizontally. The rifle is 1.9 meters above the ground. The bullet travels 200 meters horizontally before it hits the ground. What speed did Madeline's bullet have when it exited the rifle?

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pstnonsonjoku

Answer:

322.6 m/s

Explanation:

Given that there are two components of position;

x= vot

y component is;

y= 1.9 - gt^2/2

When the bullet hits the ground, y=0

1.9 -gt^2/2 =0

Where g = 10ms^-2

t= √2 × 1.9/10

t= 0.62 secs

Therefore,

x= vot

vo = x/t

Where, x= 200 m

vo= 200/0.62 =

vo= 322.6 m/s

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