Answer:
The current is [tex]I_b = 400 \ A[/tex]
Explanation:
From the question we are told that
The length of the segment is [tex]l = 2.50 \ m[/tex]
The current is [tex]I_a = 1000 \ A[/tex]
The force felt is [tex]F = 4.0 \ N[/tex]
The distance of the second wire is [tex]d = 5.0 \ cm = 0.05 \ m[/tex]
Generally the current on the second wire is mathematically represented as
[tex]I_b = \frac{2 \pi * r * F }{ l * \mu_o * I_a }[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4 \pi * 10^{-7} \ N/A^2[/tex]
=> [tex]I_b = \frac{2 * 3.142 * 0.05 * 4 }{ 2.50 * 4\pi *10^{-7} * 1000 }[/tex]
=> [tex]I_b = 400 \ A[/tex]
