9514 1404 393
Answer:
see attached
Step-by-step explanation:
The function simplifies to ...
[tex]f(x)=\dfrac{x^2-7x+12}{x-3}=\dfrac{(x-4)(x-3)}{(x-3)}\\\\\boxed{f(x)=x-4 \quad x\ne3}[/tex]
The graph has the appearance of a graph of the straight line y = x-4, but there is a hole where the function is undefined at x=3.
