Answer:
First Option {-2 , 0 , 2}
Step-by-step explanation:
A critical point occurs when the derivative is 0 or undefined.
The function in the question is undefined at x = 2 and at x = -2 because if we put x = 2 or x = -2 the denominator becomes 0 hence anything divided by 0 is undefined, and the derivative equals 0 at x = 0 so the critical points are
{-2 , 0 , 2}
Use the quotient rule to find the derivative of the function then equal it to zero
[tex]y=\frac{x^2-1}{x^2-4}\\\\\frac{dy}{dx}=\frac{(x^2-4)(2x)-(x^2-1)(2x)}{(x^2-4)^2}\\\\0=\frac{(x^2-4)(2x)-(x^2-1)(2x)}{(x^2-4)^2}\\\\0=2x^3-8x-2x^3+2x\\0=-6x\\x=0[/tex]
