Answer:
The bullet was 0.52 seconds in the air.
Explanation:
Horizontal Motion
It occurs when an object is thrown horizontally with a speed v from a height h.
The object describes a curved path ruled exclusively by gravity until it hits the ground.
To calculate the time the object takes to hit the ground, we use the following equation:
[tex]\displaystyle t=\sqrt{\frac{2y}{g}}[/tex]
Note it doesn't depend on the initial velocity but on the height.
The bullet is fired horizontally at h=1.3 m, thus:
[tex]\displaystyle t=\sqrt{\frac{2\cdot 1.3}{9.8}}[/tex]
[tex]\displaystyle t=\sqrt{\frac{2.6}{9.8}}[/tex]
t = 0.52 s
The bullet was 0.52 seconds in the air.
Any substance on this earth is directly dependent on the gravitational force. The bullet fired horizontally will also faced the gravitational pull force.
To calculate the time the object takes to hit the ground, we use the following equation:-
[tex]t=\sqrt\frac{2y}{g}[/tex]
The bullet is travelling in the air hence it does not depend on the velocity bt the mass. The height taken by the bullet is h=1.3m.
After putting the value to the equation, the answer will be as follows:-
[tex]t=\sqrt\frac{2*1.3}{9.8}[/tex]
After solving the equation the value of time is 0.52 seconds
For more information, refer to the link:-
https://brainly.com/question/17858145
