A 1405 kg car is accelerating at
1.77 m/s? Its engine creates a forward
force of 3150 N, and air resistance
creates a backward force. What is
the magnitude (+) of the force of
air resistance or the car?
(Unit = N)

Respuesta :

Answer:

fair = 663.15 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F = forces applied [N]

m = mass = 1405 [kg]

a = acceleration = 1.77 [m/s²]

In this way, we have two forces, the one that develops the engine to move the car and the resistance force of the air that opposes the movement of the car.

[tex]3150-f_{air}=m*a\\3150-f_{air}=1405*1.77\\f_{air}=3150-2486.85\\f_{air}=663.15[N][/tex]