Answer:
0 radians or 2π radians
Step-by-step explanation:
arccos(sine (StartFraction pi Over 2 EndFraction)) is expressed as;
cos^(-1) (sin π/2)
Now, (sin π/2) in radians is same as (sin 180/2) = sin 90 in degrees.
Thus;
(sin π/2) = 1
Thus;
cos^(-1) 1 = 0
It could also be 360° in the fourth quadrant since cosine is positive there too.
Thus,
cos^(-1) (sin π/2) = 0° or 360°
In radians, this gives; 0 radians or 2π radians
