Answer:
8.822 × 10¹³ g Co
General Formulas and Concepts:
Chemistry - Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
Step 1: Define
9.015 × 10³⁵ atoms Co
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Co - 58.93 g/mol
Step 3: Convert
[tex]9.015 \cdot 10^{35} \ atoms \ Co(\frac{1 \ mol \ Co}{6.022 \cdot 10^{23} \ atoms \ Co} )(\frac{58.93 \ g \ Co}{1 \ mol \ Co} )[/tex] = 8.82189 × 10¹³ g Co
Step 4: Check
We are given 4 sig figs. Follow sig fig rules and round.
8.82189 × 10¹³ g Co ≈ 8.822 × 10¹³ g Co
