The product of (3+[tex]\sqrt{-16}[/tex])(6-[tex]\sqrt{-64}[/tex]) is 50.
The given expression is (3+[tex]\sqrt{-16}[/tex])(6-[tex]\sqrt{-64}[/tex]).
We need to find the product for it.
How slove negative square roots?
Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.
Now, (3+[tex]\sqrt{-16}[/tex])(6-[tex]\sqrt{-64}[/tex])=(3+4i)(6-8i)
=18+24i-24i-32i²
=18+32=50 (∵i²=-1)
Hence, the product of (3+[tex]\sqrt{-16}[/tex])(6-[tex]\sqrt{-64}[/tex]) is 50.
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