Answer:
The magnitude and direction of the force on the charge is 120 N in the direction of the charge.
Explanation:
Given;
magnitude of the charge, q = 0.6 C
electric field strength, E = 200 N/C
The magnitude of the electric force is calculated as;
F = Eq
where;
F is the magnitude of the force
Substitute the given values and solve for F;
F = (200)(0.6)
F = 120 N in the direction of the charge.
Therefore, the magnitude and direction of the force on the charge is 120 N in the direction of the charge.
