Answer:
c. 3/2 mg
Explanation:
Given that the acceleration of an elevator is 1/2 g upward.
The reading on the scale of the elevator is the net external force acting on the elevator.
Let the force F acting on the elevator as shown,
By using Newton's 2nd law, [tex]F_{net}=ma[/tex]
where, [tex]F_{net}[/tex] is the net force acting on the elevator.
m is the mass of the elevator,
a is the acceleration of the elevator, as given a=1/2 g upward.
So, [tex]F_{net}=m\times \frac 1 2 g[/tex]
[tex]F-mg=m\times \frac 1 2 g \\\\F=mg+ \frac 1 2 mg \\\\F= \frac 3 2 mg.[/tex]
So, the reading on the scale in the elevator is [tex]\frac 3 2 mg[/tex].
Hence, option (c) is correct.
