Answer:
[tex] \red{ \boxed{ \bold{2x - 3y + 15=0}}}[/tex]
Explanation
[tex] slope \:of \:the\: required\:\: line \implies\\\frac{9-6}{6-(-3)}=\frac{6}{9} [/tex]
[tex] equation \:of \:the\: required\:\: line\implies\:\\y - 3 = \frac{6}{9} (x + 3)[/tex]
[tex] \implies \: 9y - 27 = 6x + 18[/tex]
[tex] \implies \: 6x - 9y + 45=0[/tex]
[tex] \implies\:2x-3y+15=0[/tex]
Hence the equation of the line is
[tex] \green{ \boxed{ \bold{2x - 3y + 15=0}}}[/tex]
