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Lanuel

Answer:

I. Time period = 0.2 seconds.

II. Frequency = 5 Hertz.

Explanation:

Given the following data;

Time, t = 5 seconds.

Number of oscillation, n = 25 times

I. To find the time period;

[tex] Time \; period = \frac {time}{number \; of \; oscillations}[/tex]

Substituting into the equation, we have;

[tex] Time \; period = \frac {5}{25}[/tex]

Time period = 0.2 seconds.

II. To find frequency;

[tex] Frequency = \frac {1}{Time \; period}[/tex]

Substituting into the equation, we have;

[tex] Frequency = \frac {1}{0.2}[/tex]

Frequency = 5 Hertz.

Therefore, the time period and frequency of the pendulum is 0.2 seconds and 5 Hertz respectively.

nuhulawal20
  • The time period is 0.2 seconds
  • The frequency of the pendulum is 5 Hertz

Given the data in the question;

Number of oscillation in time t; [tex]n = 25[/tex]

Time taken for the oscillation; [tex]t = 5s[/tex]

Time period

Using the expression for Time period:

[tex]Time \ period = \frac{t}{Number\ of\ oscillation}[/tex]

We substitute our given value into the equation

[tex]Time \ period = \frac{5s}{25}\\\\Time \ period = 0.2s[/tex]

Hence, the time period is 0.2 seconds

Also, using the formula for frequency:

[tex]f = \frac{1}{T}[/tex]

Where f is frequency and T is time period.

We substitute our values into the equation

[tex]f = \frac{1}{0.2s} \\\\f = 5s^{-1}\\\\f = 5Hz[/tex]

Therefore, the frequency of the pendulum is 5 Hertz.

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