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How much water must be added to 15 ml of a 2.5 M solution of sodium chloride to make a 2.0 M solution of sodium chloride?

Respuesta :

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Answer:

3.75mL need to be added

Explanation:

M1 x V1 = M2 x V2

so V2=(M1xV1)/M2

(2.5Mx.015L)/2M= .01875L or 18.75ml

since we want to know how much needs to be added we subtract 18.75 from 15

Giving us 3.75ml need to be added

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