Answer:
Following are the solution to the question:
Step-by-step explanation:
The probability of virus P(V) =0.32
No virus P(NV) =0.66
Patient testing of negative P(TN) = virus, and negative testing+no virus and negative testing
[tex]=0.32(1-0.992)+0.66 \times 0.979 \\\\=0.00256+0.64614\\\\=0.6487[/tex]
This is why the likelihood of a patient being free of the virus is negative.
[tex]= \frac{P(NV) \times\ tested \ negative }{P(TN)}[/tex]
[tex]= \frac{0.66 \times 0.979}{0.6487}\\\\= \frac{0.64614}{0.6487} \\\\=0.996053646[/tex]
