A car is going through a dip in the road whose curvature approximates a circle of radius 200 m. At what velocity will the occupants of the car appear to weigh 20% more than their normal weight (or their normal weight times 1.2)?

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Answer:

Explanation:

The solution along with the diagram can be found in the attachment. Feel free to raise doubts.

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Centripetal force is defined as the force that allows the object to follow a curvature path.

The velocity will be 19.80 m/s.

Given:

Normal Force = 1.2 x weight

Normal Force = 1.2 Mg

Mass = Mass of car + occupants

Centripetal Acceleration = [tex]\text a_c[/tex]

Now, applying the equilibrium equation:

[tex]\begin{aligned} \sum \text F&= \text m \times \text a_c\\\\\text F_n - \text{mg} &= m \times \text a_c\\\\1.2 \text{Mg} - \text{Mg} &= m \times \text a_c\\\\\text a_c &=0.2 \;\text g\\\end[/tex]

Now, substituting the value in the formula:

[tex]\begin {aligned} \text a_c &=\dfrac{\text v^2}{\text r}\\\\0.2 \text g &= \dfrac {\text v ^2}{\text r}\\\\\text v &= \sqrt{0.2 \times 9.8 \times 200}\\\\\text v &= 19.80 \;\text {m/s}\end[/tex]

Thus, the velocity will be 19.80 m/s.

To know more about centripetal acceleration, refer to the following link:

https://brainly.com/question/17689540