Answer:
Speed of a child on the rim is 4.25 m/s.
Explanation:
Given;
diameter of the merry-go-round, d = 5.0 m
period of the motion, t = 3.7 s
one complete rotation of the merry-go-round = πd
one complete rotation of the merry-go-round = π(5) = 15.71 m
Speed is given as distance / time
speed of a child on the rim = 15.71 / 3.7
speed of a child on the rim = 4.25 m/s
Therefore, speed of a child on the rim is 4.25 m/s.
