Answer:
[tex]\frac{7}{3}-\frac{2}{3}+\sqrt{3}-3\sqrt{3}=\frac{5}{3}-2\sqrt{3}[/tex]
Step-by-step explanation:
Given the expression
[tex]\frac{7}{3}\:-\:\frac{2}{3}\:+\:v^3\:-\:3v^3[/tex]
solving the expression
[tex]\frac{7}{3}\:-\:\frac{2}{3}\:+\:\sqrt{3}-3\sqrt{3}[/tex]
combine the fractions i.e [tex]\frac{7}{3}-\frac{2}{3}=\frac{5}{3}[/tex]
[tex]\frac{7}{3}\:-\:\frac{2}{3}\:+\:\sqrt{3}-3\sqrt{3}=\frac{5}{3}+\sqrt{3}-3\sqrt{3}[/tex]
add similar elements i.e [tex]\sqrt{3}-3\sqrt{3}=-2\sqrt{3}[/tex]
[tex]=\frac{5}{3}-2\sqrt{3}[/tex]
Thus,
[tex]\frac{7}{3}-\frac{2}{3}+\sqrt{3}-3\sqrt{3}=\frac{5}{3}-2\sqrt{3}[/tex]
