Given:
The line contains the point (-5,-3) and has a slope of -2.
To find:
The graph of the line.
Solution:
The line contains the point (-5,-3) and has a slope of -2. So, the equation of line is
[tex]y-y_1=m(x-x_1)[/tex]
where, m is slope.
[tex]y-(-3)=-2(x-(-5))[/tex]
[tex]y+3=-2(x+5)[/tex]
[tex]y+3=-2x-10[/tex]
Subtracting 3 from both sides, we get
[tex]y=-2x-10-3[/tex]
[tex]y=-2x-13[/tex]
So, the equation of line is [tex]y=-2x-13[/tex].
Putting x=0, we get
[tex]y=-2(0)-13[/tex]
[tex]y=0-13[/tex]
[tex]y=-13[/tex]
It means, the line also passes through (0,-13).
Plot the points (0,-13) and (-5,-3) on a coordinate plane and connect them by a straight line.
Therefore, the graph of given line is shown below.
