Timothy walks from home to a mailbox. After
walking 15 min, he puts a letter in the mailbox.
Then he walks home at the same speed. The
graph shows his distance from the mailbox
as a function of time. What is his walking speed?
A 280 ft/min © 260 ft/min
B 270 ft/min
D 250 ft/min

Timothy walks from home to a mailbox After walking 15 min he puts a letter in the mailbox Then he walks home at the same speed The graph shows his distance from class=

Respuesta :

Answer:

D. 250 feet per minute

Step-by-step explanation:

According to this question, Timothy walks at constant speed. From Physics we know that speed is the magnitude of velocity and is determined by the following definition:

[tex]v = \frac{\Delta x}{\Delta t}[/tex] (1)

Where:

[tex]\Delta x[/tex] - Distance between home and mailbox, measured in feet.

[tex]\Delta t[/tex] - Travel time, measured in minutes.

[tex]v[/tex] - Walking speed of Timothy, measured in meters per second.

The distance is represented by the vertical axis of the graph, whereas the travelling time is from the horizontal axis.

If we know that [tex]\Delta x = 3,750\,ft[/tex] and [tex]\Delta t = 15\,min[/tex], then the walking speed of Timothy is:

[tex]v = \frac{3,750\,ft}{15\,min }[/tex]

[tex]v = 250\,\frac{ft}{min}[/tex]

The walking speed of Timothy is 250 feet per minute. Hence, the right answer is D.