If bovine haemoglobin has an extinction coefficient of 30910 L mol-1 cm-1 at 570 nm in PBS, what is the concentration of a solution reading an absorbance of 0.7?

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Explanation:

The concentration of Bovine Hb with absorbance 0.7 at 570 nm has been 2.264 [tex]\mu[/tex]M.

According to Beer's law, the absorbance of the sample can be given by:

Absorbance = Extinction coefficient [tex]\rm \times[/tex] concentration [tex]\times[/tex] path length

The Bovine Hb has the extinction coefficient = 30910 L/mol/cm

The absorbance = 0.7

The path length has been 1 cm.

The concentration of the Bovine Hb can be given as:

0.7 = 30910 [tex]\times[/tex] concentration [tex]\times[/tex] 1

The concentration of Bovine Hb = 2.264 [tex]\rm \times\;10^-^6[/tex] moles/L

The concentration of Bovine Hb = 2.264 [tex]\rm \mu[/tex]moles/L

The concentration of Bovine Hb = 2.264 [tex]\mu[/tex]M.

For more information about the concentration on the basis of absorbance, refer to the link:

https://brainly.com/question/23019109