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contestada

Calculate the pH when 25.0ml of 0.90M CH3COOH is mixed with 25.0ml of 0.45M NaOH.​

Respuesta :

pH of mixed solution = 4.3

Further explanation

A buffer solution is a solution that can maintain a good pH value due to the addition of a little acid or a little base or dilution.  

The buffer solution can be acidic or basic  

Acid buffer solution consists of weak acids and their salts.  

[tex]\tt \displaystyle [H^+]=Ka\times\frac{mole\:weak\:acid}{mole\:salt\times valence}[/tex]

valence according to the amount of salt anion  

mol CH₃COOH = 25 ml x 0.9 = 22.5 mlmol

mol NaOH = 25 ml x 0.45 = 11.25 mlmol

ICE method :

Reaction

NaOH + CH₃COOH ---> CH₃COONa + H₂O

11.25       22.5

11.25       11.25                       11.25        11.25

               11.25                        11.25        11.25

mol acid = 11.25, mol salt = 11.25, Ka CH₃COOH = 5.10⁻⁵

Then [H⁺]=

[tex]\tt [H^+]=5.10^{-5}.\dfrac{11.25}{11.25\times 1}\rightarrow salt~valence=1\\\\(H^+]=5.10^{-5}\\\\pH=5-log5=4.3[/tex]