Answer:
a. T₂ = 60 N
b. W = 25.98 N
Explanation:
a.
Taking right side as positive x direction, the equation for sum of forces in x-direction can be written as follows:
[tex]T_{2}Sin\ 30^o - T_{1} = 0\\T_{2}Sin\ 30^o = T_{1}\\T_{1} = (T_{2})(Sin\ 30^o)\\where,\\T_{2} = 30\ N\\Therefore,\\T_{1} = (30\ N)(Sin\ 30^o)\\[/tex]
T₁ = 15 N
b.
Taking upward direction as positive y direction, the equation for sum of forces in y-direction can be written as follows:
[tex]T_{2}Cos\ 30^o - W = 0\\T_{2}Cos\ 30^o = W\\W = (30\ N)Cos\ 30^o\\[/tex]
W = 25.98 N
