Given that,
Initial position of the spring, x₁ = 0.25 m
Final position of the spring, x₂ = 0.1 m
The spring constant of the spring, k = 100 N/m
To find,
The elastic potential energy stored from the spring's compression.
Solution,
The work done in moving a spring from on position to another is stored in the form of elastic potential energy. It can be given as follows :
[tex]E=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 100\times (0.1^2-0.25^2)\\\\=2.62\ J[/tex]
So, the required energy is 2.62 J.
