Respuesta :

AuroraAvery

Answer:

I don't know if I'm correct but the answer is 6.

Step-by-step explanation:

I'm not 100% correct, but you set the other two angles to add to each other then set it equal to angle QRS and i got x=6.

Your equation should be like this: 3x + 17 + 2x +21 = 10x -1

than you solve form there

I;m not sure that this is the correct answer and maybe i'm wrong, but hope this helps

Hrishii

Answer:

59°

Step-by-step explanation:

According to the given description, [tex] \angle QRS[/tex] is the exterior angle of [tex] \triangle PQR[/tex]

So, by exterior angle property of a triangle, we have:

[tex] m\angle QRS=m\angle RPQ+m\angle PQR\\\\

(10x - 1)\degree = (3x +17)\degree+(2x +12)\degree\\\\

(10x - 1)\degree = (3x +17+2x +12)\degree\\\\

(10x - 1)\degree = (5x +29)\degree\\\\

(10x - 1)= (5x +29)\\\\

10x - 5x = 29 + 1\\\\

5x = 30\\\\

x = \frac{30}{5}\\\\

x = 6\\\\

\because m\angle QRS = (10x - 1)\degree \\\\

\therefore m\angle QRS = (10\times 6- 1)\degree \\\\

\therefore m\angle QRS = (60- 1)\degree \\\\

\huge\orange{\boxed{\therefore m\angle QRS = 59\degree }}\\

[/tex]

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