The complete proof is as follows:
- [tex]\mathbf{AM = CP}[/tex] -- Given
- [tex]\mathbf{CM = GP}[/tex] -- Given
- C is the midpoint of AG -- Given
- [tex]\mathbf{AC \cong CG}[/tex] --- Definition of Midpoint
- [tex]\mathbf{\triangle ACM \cong \triangle CGP}[/tex] ---- Congruent by SSS
The given parameters are:
- [tex]\mathbf{AM = CP}[/tex]
- [tex]\mathbf{CM = GP}[/tex]
- C is the midpoint of AG
This means that, the above statements would represent the first three blanks, and their respective reason is "Given"
Because of (3), above
4. [tex]\mathbf{AC \cong CG}[/tex] --- midpoint definition
(1), (2) and (4) imply that:
The three sides of both triangles are congruent by SSS
Hence, the last statement would be:
[tex]\mathbf{\triangle ACM \cong \triangle CGP}[/tex] ---- Congruent by SSS
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