Answer:
427 g Mo
General Formulas and Concepts:
Chemistry
Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Explanation:
Step 1: Define
2.68E24 atoms Mo or 2.68 × 10²⁴ atoms Mo
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Mo - 95.94 g/mol
Step 3: Convert
[tex]2.68 \cdot 10^{24} \ atoms \ Mo(\frac{1 \ mol \ Mo}{6.022 \cdot 10^{23} \ atoms \ Mo} )(\frac{95.94 \ g \ Mo}{1 \ mol \ Mo} )[/tex] = 426.966 g Mo
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
426.966 g Mo ≈ 427 g Mo
