The negative log of hydrogen or hydronium ions concentration gives the pH of the solution. The concentration of hydronium is more than the hydroxide ions.
The pH of the solution is the concentration of the hydrogen or the hydronium ion in the aqueous solution, whereas the concentration of the hydroxide ion in the solution gives the pOH.
Let the pH of the tea = 5 then,
The concentration of hydronium ion is calculated as:
[tex]\begin{aligned}\rm pH &=\rm -log[H_{3}O^{+}]\\\\\rm [H_{3}O^{+}] &= \rm 10^{-pH}\\\\&= 10 ^{-5}\end{aligned}[/tex]
The concentration of hydroxide ion is calculated as:
[tex]\begin{aligned} \rm pH &= \rm 14 - pOH \\\\&= 14 - 5\\\\&= 9\end{aligned}[/tex]
Calculating further:
[tex]\begin{aligned}\rm pOH &= \rm -log[OH^{-}]\\\\\rm [OH^{-}]& =\rm 10^{-pOH}\\\\&= 10^{-9}\end{aligned}[/tex]
Therefore, the concentration of the hydronium ion is much higher than that of the hydroxide ion.
Learn more about pH and pOH here:
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