Same formula as the last question. x = vt + (1/2)at^2. In this case, v = 0, t = 12, and a = 2.0. Plug in the values and solve for x (which is change in position)
x = (0)(12) + (1/2)(2.0)(12^2)
x = (1/2)(2.0)(144)
x = (1)(144)
x = 144
So the car will travel 144 meters in 12 seconds.
