Imagine we have mass of solvent 1kg (1000g)
According to that: [tex]molality =n(solute) / m(solvent) =\ \textgreater \ 4.8m = 4.8mole / 1kg[/tex]
= 4.8 mole * 98 g/mole = 470g
[tex]m(H2SO4) = n(H2SO4)*Mr(H2SO4) =\ \textgreater \ [/tex][tex]=\ \textgreater \ Molarity = 4.8 mole / 1.2 L = 4 M [/tex] m(H2SO4) which is =470g
m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =>
[tex]Molarity = n(solute) / V(solution) =\ \textgreater \ [/tex]
